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Omnidirectional constant transmission and negative Brewster angle at planar interfaces associated with a uniaxial medium

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Abstract

This paper presents our detailedly theoretical analyses on omnidirectional constant transmission and negative Brewster angle at planar interfaces associated with a uniaxial medium. The amplitude reflection and transmission coefficients at planar interfaces associated with uniaxial media are derived by examining the boundary condition and the dispersion relation. It is found that under certain conditions, the coefficients are constants independent of the incident angle. Another interesting phenomenon is that an interface between isotropic and uniaxial media can exhibit negative refraction under Brewster condition. Our results offer considerable potential device applications of uniaxial media.

©2009 Optical Society of America

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Figures (2)

Fig. 1
Fig. 1 Principal axes of the anisotropic medium (x,y,z) and the surface coordinates (x,y,z ).
Fig. 2
Fig. 2 (a)Brewster angles θB 1 and θB as functions of γ at the surface of Ba(NO3)2 (ε 1=1.57142) and calcite (εx =1.4862, εz =1.6582); (b)Brewster angle θB 1 and critical angle θc 1 as functions of γ at the same kind of surface.

Equations (27)

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x=xcosθ+z'sinθ,y=y,z=xsinθ+z'cosθ,
H=(0,H0,0),E=(kzH0/ωε0εx,0,kxH0/ωε0εz),
kx2/εz+kz2/εx=k02,
kix'=krx'=ktx'B,
αB2+βBkz'+γkz'2=k02εzεx,
α=εxcos2θ+εzsin2θ,β=(εxεz)sin2θ,γ=εxsin2θ+εzcos2θ.
kz±'=βB/2γ±A
A=[εzεx(γk02B2)]1/2/γ.
H=(0,H0,0),E=(γkz'+βB/2,0,αBβkz'/2)H0/ωε0εzεx.
Hi=(0,H0,0),Ei=(γA,0,αBβkiz'/2)H0/ωε0εzεx
Hr=r(0,H0,0),Er=r(γA,0,αBβkrz'/2)H0/ωε0εzεx
Ht=t(0,H0,0),Et=t(ktz',0,B)H0/ωε0ε1.
r=Hr/Hi=(γA/εzεxktz/ε1)/(γA/εzεx+ktz/ε1),
t=Ht/Hi=(2γA/εzεx)/(γA/εzεx+ktz/ε1).
S=Re[(αB+βkz'/2,0,γkz'+βB/2)H02/2ωε0εzεx].
tgθsi=Six'/Siz'=β/2γ+Bεxεz/Aγ2,
tgθsr=Srx'/Srz'=β/2γ+Bεxεz/Aγ2.
γ=ε1
εzεx=ε12.
r=[1/(εzεx)1/21/ε1]/[1/(εzεx)1/2+1/ε1].
Si=Re[(αB+βkiz'/2,0,γA)H02/2ωε0εzεx],
Sr=Re[(αB+βkrz'/2,0,γA)r2H02/2ωε0εzεx].
R=Jr/Ji=|r|2.
T=1|r|2
B2=(εxεzε1γ)ε1k02/(εxεzε12),
tan2θB1=(εxεzε1γ)/(ε1γε12).
tan2θB1/(tanθB2±±|β|/2γ)2=ε12/γ2.
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